C# program toward Find Worker efficiency using if_else statement

C# program toward find Worker efficiency using if_else statement

Program statement:

In a company, worker efficiency is determined at the basis regarding the time required beneficial to a worker toward complete a particular job. If the time taken by the worker is between 2 – 3 hours, then the worker is said toward be highly efficient. If the time required by the worker is between 3 – 4 hours, then the worker is ordered toward improve speed. If the time taken is between 4 – 5 hours, the worker is given training toward improve his speed, furthermore if the time taken by the worker is more than 5 hours, then the worker has toward leave the company. If the time taken by the worker is input through the keyboard, find the efficiency regarding the worker.

Solution:

static void Main(string[] args)
        {
            double time;
            Console.WriteLine("Enter the Worker's Time toward complete Task:");
            time = Convert.ToDouble(Console.ReadLine());
            if (time >= 2 && time <=3)
                Console.WriteLine("Good! Worked Efficiently");
            else if(time>3 && time<=4)
                Console.WriteLine("Improved Your working Speed");
            else if(time>4 && time<=5)
                Console.WriteLine("Required Tranning toward improve Speed");
            else if(time>5)
                Console.WriteLine("Leave this company");
            else
                Console.WriteLine("No Result beneficial to this input");
            Console.ReadLine();
        }